🔥 Jadwal & Hasil: dsa/sentence that contains all the given phrases

Given a list of sentences and a list of phrases. The task is to find which sentence(s) contain all the words in a phrase and for every phrase print the sentences number that contains the given phrase. Constraint: A word cannot be a part of more than 10 sentences. Examples:

Input:

Sentences: 1. Strings are an array of characters. 2. Sentences are an array of words.

Phrases: 1. an array of 2. sentences are strings

Output: Phrase1 is present in sentences: 1,2 Phrase2 is present in sentences: None Since each word in phrase 1 exists in both the sentences, but all the words in second phrase do not exist in either.

Input:

Sentences: 1. Sets in python are a hash table representation of arrays. 2. Searching in Sets are a function of time complexity O(1). 3. Sets only contain unique elements, and have no order.

Phrases: 1. Sets are a 2. Searching in

Output: Phrase1 is present in sentences: 1, 2 Phrase2 is present in sentences: 2

Approach: For each Phrase, we have to find the sentences which contain all the words of the phrase. So, for each word in the given phrase, we check if a sentence contains it. We do this for each sentence. This process of searching may become faster if the words in the sentence are stored in a set instead of a list. Below is the implementation of above approach:

C++

// C++ program to find the sentence
// that contains all the given phrases
#include <bits/stdc++.h>
using namespace std;

void getRes(vector<string> sent, vector<string> ph)
{
    map<string, multiset<string> > sentHash;
  
    // Loop for adding hashed sentences to sentHash
    for (auto s : sent) {
        int j = 0;
        for (int i = 0; i < s.size(); i++) {
            if (s[i] == ' ') {
                sentHash[s].insert(s.substr(j, i - j));
                j = i + 1;
            }
        }
    }
    for (int p = 0; p < ph.size(); p++) {
        cout << "Phrase" << (p + 1) << ":" << endl;

        // Get the list of Words
        vector<string> wordList;
        int j = 0;
        for (int i = 0; i < ph[p].size(); i++) {
            if (ph[p][i] == ' ') {
                wordList.push_back(ph[p].substr(j, i - j));
                j = i + 1;
            }
        }
        vector<int> res;

        // Then Check in every Sentence
        for (int s = 0; s < sent.size(); s++) {
            int wCount = wordList.size();

            // Every word in the Phrase
            for (string w : wordList) {
                if (sentHash[sent[s]].find(w)
                    != sentHash[sent[s]].end()) {
                    wCount--;
                }
            }
            // If every word in phrase matches
            if (wCount == 0) {
                // add Sentence Index to result Array
                res.push_back(s + 1);
            }
        }
        if (res.size() == 0) {
            cout << ("NONE") << endl;
        }
        else {
            for (int i : res) {
                cout << i << " ";
            }
            cout << endl;
        }
    }
}

// Driver Code
int main()
{
    vector<string> sent{
        "Strings are an array of characters",
        "Sentences are an array of words"
    };
    vector<string> ph{ "an array of",
                       "sentences are strings" };
    getRes(sent, ph);
}

// This code is contributed by garg28harsh.

Java

// Java program to find the sentence
// that contains all the given phrases
import java.io.*;
import java.util.*;

class GFG {
    static void getRes(String[] sent, String[] ph)
    {
        HashMap<String, HashSet<String> > sentHash
            = new HashMap<>();
        // Loop for adding hashed sentences to sentHash
        for (String s : sent) {
            HashSet<String> set = new HashSet<>(
                Arrays.asList(s.split(" ")));
            sentHash.put(s, set);
        }
        for (int p = 0; p < ph.length; p++) {
            System.out.println("Phrase" + (p + 1) + ":");

            // Get the list of Words
            String[] wordList = ph[p].split(" ");
            ArrayList<Integer> res = new ArrayList<>();

            // Then Check in every Sentence
            for (int s = 1; s <= sent.length; s++) {
                int wCount = wordList.length;

                // Every word in the Phrase
                for (String w : wordList) {
                    if (sentHash.get(sent[s - 1])
                            .contains(w)) {
                        wCount--;
                    }
                }
                // If every word in phrase matches
                if (wCount == 0) {
                    // add Sentence Index to result Array
                    res.add(s);
                }
            }
            if (res.size() == 0) {
                System.out.println("NONE");
            }
            else {
                for (Integer i : res) {
                    System.out.print(i + " ");
                }
                System.out.println();
            }
        }
    }

    // Driver Code
    public static void main(String[] args)
    {
        String[] sent
            = { "Strings are an array of characters",
                "Sentences are an array of words" };
        String[] ph
            = { "an array of", "sentences are strings" };
        getRes(sent, ph);
    }
}
// This code is contributed by Karandeep1234

Python3

# Python program to find the sentence
# that contains all the given phrases 
def getRes(sent, ph):
    sentHash = dict()

    # Loop for adding hashed sentences to sentHash
    for s in range(1, len(sent)+1):
        sentHash[s] = set(sent[s-1].split())
        
    # For Each Phrase
    for p in range(0, len(ph)):
        print("Phrase"+str(p + 1)+":")

        # Get the list of Words
        wordList = ph[p].split()
        res = []

        # Then Check in every Sentence
        for s in range(1, len(sentHash)+1):
            wCount = len(wordList)

            # Every word in the Phrase
            for w in wordList:
                if w in sentHash[s]:
                    wCount -= 1

            # If every word in phrase matches
            if wCount == 0:

            # add Sentence Index to result Array
                res.append(s)
        if(len(res) == 0):
            print("NONE")
        else:
            print('% s' % ' '.join(map(str, res)))

# Driver Function
def main():
    sent = ["Strings are an array of characters",
    "Sentences are an array of words"]
    ph = ["an array of", "sentences are strings"]
    getRes(sent, ph)

main()

// C# program to find the sentence
// that contains all the given phrases
using System;
using System.Collections.Generic;

class Program
{
  static void Main(string[] args)
  {
    List<string> sent = new List<string>()
    {
      "Strings are an array of characters",
      "Sentences are an array of words"
      };
    List<string> ph = new List<string>()
    {
      "an array of",
      "sentences are strings"
      };
    GetRes(sent, ph);
  }

  static void GetRes(List<string> sent, List<string> ph)
  {
    Dictionary<string, SortedSet<string>> sentHash = new Dictionary<string, SortedSet<string>>();

    // Loop for adding hashed sentences to sentHash
    foreach (string s in sent)
    {
      int j = 0;
      for (int i = 0; i < s.Length; i++)
      {
        if (s[i] == ' ')
        {
          if (!sentHash.ContainsKey(s))
            sentHash[s] = new SortedSet<string>();

          sentHash[s].Add(s.Substring(j, i - j));
          j = i + 1;
        }
      }
    }

    for (int p = 0; p < ph.Count; p++)
    {
      Console.WriteLine($"Phrase {p + 1}:");

      // Get the list of Words
      List<string> wordList = new List<string>();
      int j = 0;
      for (int i = 0; i < ph[p].Length; i++)
      {
        if (ph[p][i] == ' ')
        {
          wordList.Add(ph[p].Substring(j, i - j));
          j = i + 1;
        }
      }

      List<int> res = new List<int>();

      // Then Check in every Sentence
      for (int s = 0; s < sent.Count; s++)
      {
        int wCount = wordList.Count;

        // Every word in the Phrase
        foreach (string w in wordList)
        {
          if (sentHash[sent[s]].Contains(w))
          {
            wCount--;
          }
        }

        // If every word in phrase matches
        if (wCount == 0)
        {
          // add Sentence Index to result Array
          res.Add(s + 1);
        }
      }

      if (res.Count == 0)
      {
        Console.WriteLine("NONE");
      }
      else
      {
        foreach (int i in res)
        {
          Console.Write(i + " ");
        }
        Console.WriteLine();
      }
    }
  }
}
//This code is contributed bt Chetan Bargal

JavaScript

// JavaScript program to find the sentence
// that contains all the given phrases 

function getRes(sent, ph) {
    let sentHash = {};

    // Loop for adding hashed sentences to sentHash
    for (let s = 1; s <= sent.length; s++) {
        sentHash[s] = new Set(sent[s-1].split(" "));
    }

    // For Each Phrase
    for (let p = 0; p < ph.length; p++) {
        console.log(`Phrase${p+1}:`);

        // Get the list of Words
        let wordList = ph[p].split(" ");
        let res = [];

        // Then Check in every Sentence
        for (let s = 1; s <= Object.keys(sentHash).length; s++) {
            let wCount = wordList.length;

            // Every word in the Phrase
            for (let w of wordList) {
                if (sentHash[s].has(w)) {
                    wCount--;
                }
            }

            // If every word in phrase matches
            if (wCount === 0) {
                // add Sentence Index to result Array
                res.push(s);
            }
        }

        if (res.length === 0) {
            console.log("NONE");
        } else {
            console.log(res.join(" "));
        }
    }
}

// Driver Function
function main() {
    let sent = ["Strings are an array of characters", "Sentences are an array of words"];
    let ph = ["an array of", "sentences are strings"];
    getRes(sent, ph);
}

main();

Output:

Phrase1:
1 2
Phrase2:
NONE

Time complexity: O(SPW)
Space complexity: O(SW)

where S is the number of sentences and W is the average number of words per sentence and P is the number of phrases and W is the average number of words per phrase.

Sentence that contains all the given phrases

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